P11.046 (Multistep) A W530 X 66 structural steel [E = 200 GPa) wide-flange shape is loaded…

P11.046 (Multistep) A W530 X 66 structural steel [E = 200 GPa) wide-flange shape is loaded and supported as shown in the figure. A uniformly distributed load of w = 66 kN/m is applied to the beam, causing the roller support at B to settle downward (i.e., displace downward) by d = 8 mm. Determine: (a) the reactions at supports A and B. (b) the maximum bending stress in the beam. Assume a = 5.5 m and b = 1.3 m. W x Incorrect. The total deflection at B is the sum of the deflection due to the uniformly distributed load w and the support reaction force By. The deflection due to w is negative and has been determined. The deflection due to By is positive and it was found as a function of By in Step 3. Set the sum of these two components of the deflection equal to -8 mm and solve for By. The value entered here for By should be positive. Determine the vertical support reaction force By required to make the total beam deflection at B equal to the distance by which support B settles downward (i.e., VB = -8 mm). Enter a positive value if By acts upward on the beam, or a negative value if it acts downward. By = 249 KN Part 5 Calculate the reaction force Ay and the reaction moment MA acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. The reaction force B, has already been determined. It acts upward on the beam, so it is positive. IIIIIIIIIIII IC IN MA = KN.m Part 6 Determine the maximum magnitude moment at any location in the beam and the maximum magnitude bending stress at any location in the beam. Enter positive values for these magnitudes. Note: Use the tabulated value for the section modulus S from Step 1 directly in the stress calculation. Although S is related to the area moment of inertial and the cross-section depth d, due to round-off in the tabulated data for S. I, and d, a slightly different answer for the bending stress is obtained using S directly as compared to the result obtained in using / and d. Of course, performing the calculation using either S directly, or using 1 and d, the answer will likely be within the required tolerance. Minas = 1 Omax = KN.m _MP_ Click if you would like to Show Work for this question: Open Show Work